| 1 | // REQUIRES: target-is-powerpc64le |
| 2 | // RUN: %clang_builtins %s %librt -o %t && %run %t |
| 3 | |
| 4 | /* |
| 5 | * Test case execution for: long double __floattitf (__int128_t) |
| 6 | * Conversion from 128 bit integer to long double (IBM double-double). |
| 7 | */ |
| 8 | |
| 9 | #include <stdint.h> |
| 10 | #include <stdio.h> |
| 11 | |
| 12 | #include "floattitf_test.h" |
| 13 | |
| 14 | /* The long double representation, with the high and low portions of |
| 15 | * the long double, and the corresponding bit patterns of each double. */ |
| 16 | typedef union { |
| 17 | long double ld; |
| 18 | double d[2]; /* [0] is the high double, [1] is the low double. */ |
| 19 | unsigned long long ull[2]; /* High and low doubles as 64-bit integers. */ |
| 20 | } ldUnion; |
| 21 | |
| 22 | long double __floattitf(__int128_t); |
| 23 | |
| 24 | int main(int argc, char *argv[]) { |
| 25 | /* Necessary long double and 128 bit integer declarations used to |
| 26 | * compare computed and expected high and low portions of the |
| 27 | * IBM double-double. */ |
| 28 | ldUnion expectedLongDouble; |
| 29 | ldUnion computedLongDouble; |
| 30 | __int128_t result128; |
| 31 | |
| 32 | for (int i = 0; i < numTests; ++i) { |
| 33 | /* Set the expected high and low values of the long double, |
| 34 | * and the 128 bit integer input to be converted. */ |
| 35 | expectedLongDouble.d[0] = tests[i].hi; |
| 36 | expectedLongDouble.d[1] = tests[i].lo; |
| 37 | result128 = tests[i].input128; |
| 38 | |
| 39 | /* Get the computed long double from the int128->long double conversion |
| 40 | * and check for errors between high and low portions. */ |
| 41 | computedLongDouble.ld = __floattitf(result128); |
| 42 | |
| 43 | if ((computedLongDouble.d[0] != expectedLongDouble.d[0]) || |
| 44 | (computedLongDouble.d[1] != expectedLongDouble.d[1])) { |
| 45 | |
| 46 | printf(format: "Error on __floattitf( 0x%016llx 0x%016llx ):\n" , |
| 47 | (long long)(tests[i].input128 >> 64), |
| 48 | (long long)tests[i].input128); |
| 49 | printf(format: "\tExpected value - %La = ( %a, %a )\n" , expectedLongDouble.ld, |
| 50 | expectedLongDouble.d[0], expectedLongDouble.d[1]); |
| 51 | printf(format: "\tComputed value - %La = ( %a, %a )\n\n" , computedLongDouble.ld, |
| 52 | computedLongDouble.d[0], computedLongDouble.d[1]); |
| 53 | |
| 54 | return 1; |
| 55 | } |
| 56 | } |
| 57 | |
| 58 | return 0; |
| 59 | } |
| 60 | |