1 | // Check that merging of MIB info (min/max size and access counts specifically) |
2 | // is done correctly. |
3 | |
4 | // RUN: %clangxx_memprof -O0 %s -o %t |
5 | // RUN: %env_memprof_opts=print_text=true:log_path=stderr %run %t 2>&1 | FileCheck %s |
6 | |
7 | // This is actually: |
8 | // Memory allocation stack id = STACKID |
9 | // alloc_count 2, size (ave/min/max) 60.00 / 40 / 80 |
10 | // but we need to look for them in the same CHECK to get the correct STACKID. |
11 | // CHECK: Memory allocation stack id = [[STACKID:[0-9]+]]{{[[:space:]].*}}alloc_count 2, size (ave/min/max) 60.00 / 40 / 80 |
12 | // CHECK-NEXT: access_count (ave/min/max): 30.00 / 20 / 40 |
13 | // Unfortunately there is not a reliable way to check the ave/min/max lifetime. |
14 | // CHECK-NEXT: lifetime (ave/min/max): |
15 | // CHECK-NEXT: num migrated: {{[0-1]}}, num lifetime overlaps: 0, num same alloc cpu: {{[0-1]}}, num same dealloc_cpu: {{[0-1]}} |
16 | // CHECK: Stack for id [[STACKID]]: |
17 | // CHECK-NEXT: #0 {{.*}} in operator new |
18 | // CHECK-NEXT: #1 {{.*}} in main {{.*}}:[[@LINE+7]] |
19 | |
20 | #include <stdio.h> |
21 | #include <stdlib.h> |
22 | |
23 | int main() { |
24 | for (int j = 1; j < 3; j++) { |
25 | int *p = new int[10 * j]; |
26 | for (int i = 0; i < 10 * j; i++) |
27 | p[i] = i; |
28 | int a = 0; |
29 | for (int i = 0; i < 10 * j; i++) |
30 | a += p[i]; |
31 | delete[] p; |
32 | } |
33 | |
34 | return 0; |
35 | } |
36 | |