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1
extern
int
g1
,
g2
;
2
extern
void
foo
(
int
n
);
3
4
int
main
() {
5
int
i
,
j
;
6
for
(
i
=
0
;
i
<
1000
;
i
++)
7
for
(
j
=
0
;
j
<
1000
;
j
++)
8
foo
(
n:
i
*
j
);
9
10
if
(
g2
-
g1
==
280001
)
11
return
0
;
12
return
1
;
13
}
14