| 1 | // RUN: %libomp-compile-and-run |
| 2 | // UNSUPPORTED: gcc |
| 3 | // This test is incompatible with gcc because of the explicit call to |
| 4 | // __kmpc_doacross_fini(). gcc relies on an implicit call to this function |
| 5 | // when the last iteration is executed inside the GOMP_loop_*_next() functions. |
| 6 | // Hence, in gcc, having the explicit call leads to __kmpc_doacross_fini() |
| 7 | // being called twice. |
| 8 | #include <stdio.h> |
| 9 | |
| 10 | #define N 1000 |
| 11 | |
| 12 | struct dim { |
| 13 | long long lo; // lower |
| 14 | long long up; // upper |
| 15 | long long st; // stride |
| 16 | }; |
| 17 | extern void __kmpc_doacross_init(void*, int, int, struct dim *); |
| 18 | extern void __kmpc_doacross_wait(void*, int, long long*); |
| 19 | extern void __kmpc_doacross_post(void*, int, long long*); |
| 20 | extern void __kmpc_doacross_fini(void*, int); |
| 21 | extern int __kmpc_global_thread_num(void*); |
| 22 | |
| 23 | int main() |
| 24 | { |
| 25 | int i; |
| 26 | int iter[N]; |
| 27 | struct dim dims; |
| 28 | for( i = 0; i < N; ++i ) |
| 29 | iter[i] = 1; |
| 30 | dims.lo = 1; |
| 31 | dims.up = N-1; |
| 32 | dims.st = 1; |
| 33 | #pragma omp parallel num_threads(4) |
| 34 | { |
| 35 | int i, gtid; |
| 36 | long long vec; |
| 37 | gtid = __kmpc_global_thread_num(NULL); |
| 38 | __kmpc_doacross_init(NULL,gtid,1,&dims); // thread starts the loop |
| 39 | #pragma omp for nowait schedule(dynamic) |
| 40 | for( i = 1; i < N; ++i ) |
| 41 | { |
| 42 | // runtime call corresponding to #pragma omp ordered depend(sink:i-1) |
| 43 | vec=i-1; |
| 44 | __kmpc_doacross_wait(NULL,gtid,&vec); |
| 45 | // user's code |
| 46 | iter[i] = iter[i-1] + 1; |
| 47 | // runtime call corresponding to #pragma omp ordered depend(source) |
| 48 | vec=i; |
| 49 | __kmpc_doacross_post(NULL,gtid,&vec); |
| 50 | } |
| 51 | // thread finishes the loop (should be before the loop barrier) |
| 52 | __kmpc_doacross_fini(NULL,gtid); |
| 53 | } |
| 54 | if( iter[N-1] == N ) { |
| 55 | printf(format: "passed\n" ); |
| 56 | } else { |
| 57 | printf(format: "failed %d != %d\n" , iter[N-1], N); |
| 58 | return 1; |
| 59 | } |
| 60 | return 0; |
| 61 | } |
| 62 | |
| 63 | |