| 1 | for (int c0 = 1; c0 < max((6 * M + 3 * N + 188) / 200 - 2, (N + 93) / 100 + 3 * ((2 * M + N - 4) / 200) - 1); c0 += 1) |
|---|---|
| 2 | for (int c1 = max(0, floord(-N + 100 * c0 + 106, 300)); c1 <= min((2 * M + N - 4) / 200 - 1, (c0 - 1) / 3); c1 += 1) |
| 3 | S2(c0 - c1, c1); |
| 4 |